If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3+13x-4x^2=0
a = -4; b = 13; c = +3;
Δ = b2-4ac
Δ = 132-4·(-4)·3
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{217}}{2*-4}=\frac{-13-\sqrt{217}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{217}}{2*-4}=\frac{-13+\sqrt{217}}{-8} $
| 0.82*x=1 | | 128x=180 | | 2m-5/3+3m+2/5=4m-3/3-5m+2/3 | | 7-9x=11x-8 | | (2x+1)(3x+-5)= | | -3x-16=12-x | | 8x+23=4x+26 | | 20c^2+15c=0 | | -5+n|4=-1 | | 2(y-3)-4(y-2)=5y+6+6(y-7) | | 0,5x-3=0 | | 6x-6=-27 | | P/5-3/8=3p/4+7/4 | | Y=0.2x^2+0x+3 | | 90=x+(3x+12) | | 48−m=20 | | 7x-70=3x-10 | | 4x^2=0.5 | | x(2x−5)=0 | | 10x+(100-x)11÷100=0 | | 5(x-3)-4(2x-9)=0 | | y-5y=2 | | 2^x+2^99x=4 | | 2^x+2^(99x)=2^2 | | 2^x+2^99x=2^2 | | X²+y²=49 | | 5m-6=2m+4 | | 9.5-x=2 | | (x*0.85)+x=60 | | 5m+9/2=19/2 | | F(4x)=8(4x)-3 | | F(4x)=8x-3 |